Capacity of flight conveyor in tons$/$hr is given by $($where$,$ W & D $=$ width and depth of flight respectively in metre V $=$ speed of the conveyor, metre$/$second $=$ bulk density of material, kg$/$m$3)$

$3\mathrm{.}6$ W$.$D$.$V$.$

$3\mathrm{.}6$ W$.$D$.$V

$3\mathrm{.}6$ W$.$V$.$

$3\mathrm{.}6$ D$.$V$.$