Casino games of pure chance(e.g., craps,roulette, baccarat, andkeno) always yield a"house advantage." Forexample, in the game ofdouble-zero roulette, the expected casino win percentage is 5.23% on bets made on whether the outcome will be either black or red.(This implies that for every$5 bet on black orred, the casino will earn a net of about 23 cents.) It can be shown that in 100 roulette plays onblack/red, the average casino win percentage is normally distributed with mean 5.23% and standard deviation 11%. Let x represent the average casino win percentage after 100 bets onblack/red indouble-zero roulette. Complete parts a through d.

a. Find P(x > 0). (This is the probability that the casino winsmoney.)

P(x > 0) =

(Round to three decimal places asneeded.)

b. Find P(4 < x < 15).

P(4 < x < 15) =

(Round to three decimal places asneeded.)

c. Find P(x < 2).

P(x < 2) =

(Round to three decimal places asneeded.)

d. If you observed an average casino win percentage of 25% after 100 roulette bets onblack/red, what would youconclude?

A. The probability of an average casino win percentage of minus 25% is verylarge, near 1. The casino is losing money.

B. The probability of an average casino win percentage of minus 25% is verysmall, near 0. The casino is winning money.

C. The probability of an average casino win percentage of minus 25% is verysmall, near 0. The casino is losing money.

D. The probability of an average casino win percentage of minus 25% is verylarge, near 1. The casino is winning money.