CHANGE THE CODE so that it reads 4 difderent inreger values from the user: N1, N2, N3 and N4. All values may be positive, negative or zero.

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include c: \asmio\asm32.inc

includelib c:\asmio\asm32.lib

includelib c:\asmio\user32.lib

includelib c:\asmio\kernel132.lib

.const

NULL = 0

.data?

n1 dword ?

n2 dword ?

.data

Input byte "Enter a number: ", NULL

sumMs byte "N1 + N2 = ", NULL

difMs byte "N1 - N2 = ", NULL

.code

main proc

mov edx, OFFSET Input

call WriteString

call readInt

mov n1, eax

mov edx, OFFSET Input

call WriteString

call readInt

mov n2, eax

add eax, nl

call crLf

mov edx, OFFSET sumMs

call WriteString

call writeInt

mov eax, n1

mov eax, n2

call crLf

mov edx, OFFSET difMs

call WriteString

call WriteInt

call readInt

ret 0

main endp

end main

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3. Change the code so that it reads 4 different integer values from the user: N1, N2, N3 and N4. All values may be positive, negative or zero. 4. After the user input the four values about compute the following quantity N1 + 2*N2 - N3 Note: (1) The final result of the expression above has to be in register EAX for printing. (2) Both addition and subtraction must be done through a register. In Assembler it is not allowed to add or subtract two numbers directly such as in: add N1,N2. To add two variables we need to use the register eax instead. For example, to compute 2 *N2 we need to add N2 twice in register eax, such as: mov eax, N2 ; move N2 to eax register add N2, eax ; add eax = N2 to N2 = 2 * N2 5. Keep the final result above in the EAX register for printing (See lines 57 - 60). 6. Prepare the final message below by creating the variable below in the .data segment: Output byte "The final result ", NULL 7. Check that your program produced the correct amount for the values: N1 N2 N3 3 Answer -10 -4 ON OWN 0 2