Chapter 16 Question 16.9

16.9 Given the aggression scores below for Outcome A of the sleep deprivation experiment, verify that, as suggested earlier, these mean differences shouldn't be taken seriously by testing the null hypothesis at the .05 level of significance. Use the computation formulas for the various sums of squares and summarize results with an ANOVA table.

HOURS OF SLEEP DEPRIVATION ZERO TWENTY-FOUR FORTY-EIGHT 3 4 2 5 8 4 7 6 6

Group mean: 5 6 4

Grand mean = 5

Answer( s ) and commentary ( please show work ):

Include SPSS output please