ChBE 3610 Chemical Engineering Kinetics & Reactor Design Homework #7 Enzyme Reactions The following model is proposed for uncompetitive inhibition: E+ SES ES_> P + E ES + IT-ES 1 - In this model the inhibitor binds to the ES complex and not to enzyme directly (if it binds directly to the enzyme it is called competitive inhibition). (1) Derive the production rate of species P (Rp) and species S (-Rs) applying quasi steady state approximation (QSSA) to both ES and I-ES complex. Define an inhibition constant K1=kz/k3, show that for large values of the inhibition constant that your production rates recover the original Michaelis-Menten rate law for enzymes with no inhibition. Recall that this result, found in the slides, is the following: Vmaxes " IT Cs+K kitk K. ki Vmax = K0 Eronat