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Cheetahs can accelerate to a speed of 20.0 m/s in 2.50 s and can continue to accelerate to reach a top speed of 28.6
Cheetahs can accelerate to a speed of 20.0 m/s in 2.50 s and can continue to accelerate to reach a top speed of 28.6 m/s. Assume the acceleration is constant until the top speed is reached and is zero thereafter. Let the +x-direction point in the direction the cheetah runs. Express the cheetah's top speed Utop in miles per hour (mi/h). Utop = taccel = X d = Enter numeric value Starting from a crouched position, how much time taccel does it take a cheetah to reach its top speed, and what distance d does it travel in that time? mi/h S m If a cheetah sees a rabbit 136.0 m away, how much time ttotal will it take to reach the rabbit, assuming the rabbit does not move and the cheetah starts from rest?
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