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Chemical and environmental engineers are increasingly interested in recovering resources from waste streams. Given the high costs of the Haber - Bosch process you decide

Chemical and environmental engineers are increasingly interested in recovering resources from waste streams. Given the high costs of the Haber-Bosch process you decide to look into ammonia release and recovery from urea. Consider the enzymatic reaction,
NHCONH2(Urea)+ Urease + H2O 2 NH3+ CO2+ Urease
The rate law for the reaction is
-r_{U}=\frac{kC_{U}}{K_{M}+C_{U}}
The following data were collected at 25^{\circ}C:
-nU(mol~g^{-1}min^{-1})
5.92\times10^{-6}
\frac{5.44\times10^{-5}}{10^{-5}}
5.43\times10^{-4}
3.98\times10^{-3}
\frac{.36\times10^{-2}}{10c^{2}}
1.66\times10^{-2}
1.86\times10^{-2}
Cu \overline{(mol~L^{-1})}
\frac{5.92\times10^{-6}}{10^{-6}}
10^{-4}
10^{-3}
10^{-1}
\overline{10^{0}}
(a) What are the values of k and K_{M}\overline{?}
(b) Generate a curve for -r_{v} as a function of C_{U}. Your x-axis should range from C_{11}=10^{-6} to 10^{\circ} using a logarithmic scale. Comment on the goodness of fit..
(c) If the activation energy is 35.3 kJ mol, plot -r_{u} vs. Cu at 37^{\circ}C Overlay the -r_{u} curve for 37^{\circ}C onto your plot from (c). Explain differences observed for the two temperatures.

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