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Chemical Engineering Department Introduction to Materials Science and Engincering (219CHE) Lormewnark. 2 (20points) - Q1 - Energy for secondary bonding can be expressed as: E=KA/r6+KR/r12 Where Kn and KR are constant for attraction and repulsion, respectively. Given KA=10.37107sJm6 and KR=16.16101sJmt2, for argon. I- Calculate the bond energy in J and bond length in nm for argon. (Class work) 2- Plot the bonding cnergy curve (take r over the range 0.33 to 0.8nm ), On the basis of this plot, determine the bond energy in J and bond length in nm for argon. (20 points) 3- Plot the secondary bonding force curve for argon, that is, F versus r over the same range. (Class work) Q-2 What type(s) of bonding would be expected for each of the following materials: solid xenon, calcium fluoride ( CaF2 ), bronze, and tungsten? (Class work) Q-3 What is the type of bonding in diamond? Are the properties of diamond matching the nature of bonding? What are some of the industrial applications of diamond? (Class work)