Chemical reactions do not take place instantaneously, and indeed often proceed rather slowly. In such cases, it is not practical to design the reactor for complete conversion of the limiting reactant; instead, the reactor effluent emerges with some of the limiting reactant still present and is then usually subjected to a separation process to remove the unconverted reactant from the product. The separated reactant is then recycled back to the reactor inlet. In this assignment, you will use Microsoft Excel to solve a material and energy balance problem for a given reaction involving recycle. You will be expected to be able to use spreadsheets in industry in performing a variety of works.

$2.$ Spreadsheet to be designed

The spreadsheet each group must design should allow a user to input reactant flows $($in mol$/$min$)$ and a conversion of one of the reactants, into a reactor at known inlet and outlet temperatures. The process should be able to recycle the expensive reactant in excess back to the reactor as shown in the figure below. Then, based upon the conversion, reaction stoichiometry and user input values for the specific heat capacity relationship, and heat of reaction, calculate the output from the reactor, the enthalpy change within the reactor and thus the energy which would need to be added or removed from the reactor to maintain the outlet temperature.

User Inputs $($Please highlight these on the spreadsheet for ease of use$)$:

Reactant flows $($mol$/$min$)$

Stoichiometric coefficients for the reaction

Conversion of one reactant

Specific Heat calculation for each reactant and product

Heat of Reaction

Reactor Inlet temperature

Reactor Outlet temperature.

Outputs:

Reactor Outlet molar flows of each component $($mol$/$min$),$

Total molar flow $($mol$/$min$)$ and mole fractions in the outlet $($mol$/$mol$)$

Enthalpy In and Enthalpy Out for each component and the total in the inlet and outlet streams$($kJ$/$min$)$

Enthalpy change for the reactor $($including the heat of reaction$)$ kJ$/$min

wirh $4$NH$3+5$O$2-->4$NO $+6$H$20$