Given below the half reaction of certain specles with E vs SCE, whlch one of them can't be determined using polarography method or technique In aqueous solutions. O cu?t + 2e cu(Hg) E = +0.069 V %3! O Zn?* + 2e- Zn(Hg) E = -1.000 V Fet + e- Fe2 E = +0.503 V O ca* +2e ca(Hg) E = -0.603 V E= +0.067 V O UO,2* + 4H+ + 2e-u4* + 2H,O