Chi Square analysis:

Tom Brady is the recreation director for a large university. He is worried about the fitness level of the students and is interested to know if the accommodation choice of the students is related to their level of exercise. He will use this data to help plan future fitness programs.

Accommodation	No Regular Exercise	Sporadic Exercise	Regular Exercise	Total
Dormitory	32	30	28	90
On-Campus Apartment	74	64	42	180
Off-Campus Apartment	110	25	15	150
At Home	39	6	5	50
Total	255	125	90	470

Using a significance level of 0.05, the chi-square statistic is 60.4394. The p-value is < 0.00001

Required:

1. Write the null and alternate hypotheses for this data. (2 marks)
2. Evaluate what the chi square results mean. (4 marks)
3. Based on the results, what decisions or further research might Tom make? (4 marks)