CHOOSE THE CORRECT OPTION

You need to compare 2 different cases below, note that in the second case there is a larger difference between the means.

CASE1

	group 1	group 2
mean	1689.3	1680
standard deviation	80	60
sample size	100	100

Test stat for two sample t test 0.93 verify this using a computer also calculate the pvalues for testing the claim there is a difference.

CASE 2

	group 1	group 2
mean	1698.6	1680
standard deviation	80	60
sample size	100	100

Test stat for two sample t test 1.86 verify this using a computer also calculate the pvalue for testing if there is a difference.

CHOOSE THE CORRECT OPTION:

a.the sample proportion in group 1 is 20.93

b.For case 2 the pvalue is 0.70

c.For case 1 the pvalue is 0.35

d.For case 2 the pvalue is 0.06

e.For case 2 the pvalue is -0.17

f.When you compare case 1 with case 2, case 2 has a bigger difference between the means so the p-value is smaller

g.When you compare case 1 with case 2, case 2 has a larger sample size so there is more evidence that the population means are different so the p-value is higher