Choose the equivalent grammar in Greibach normal form to the one

below:

$S$aaSbS$|b$

$S$aaSBS$|B$

$Bb$

$S$aASBS$|b$

$Aa$

$Bb$

$S$aASB$|S|b$

$Aa$

$Bb$

Not possible, this grammar is not linear.