Chrome File Edit View History Bookmarks Profiles Tab Window Help O ? Q . Thu Feb 16 9:55 AM VA HW4_Spring2023_Electric Fiel X Course Hero X + - > C webassign.net/web/Student/Assignment-Responses/last?dep=31402671 GOXAI Update 0.500 m 60.0 42140.250 m- VE Since the altitude h of the triangle is perpendicular to its base and the triangle is equilateral, h = 0.500 0.5 m sin( 60 60 0) = 0.433 0.433 m. Step 2 The magnitude of E, is given by IE1 1 = 61 = Ke 191 1 2 where ke is Coulomb's constant and r, is the distance, h, of P from q1 . We have 191 - 191 1 E1 = ker,2 = ke 2 x 10-6 c) = (8.99 x 109 N . m2/C2 m) = x 105 N/C. The vector E, is along the negative y-direction so it has no horizontal component, that is, Ex = 0, and, for its vertical component, Ely, we have Ely = -61 = - x 10'5 N/C. Submit Skip (you cannot come back)