Class Management | Help PS6(a)--ApplicationsOfWork Begin Date: 5/8/2023 12:01:00 AM -- Due Date: 5/16/2023 11:59:00 PM End Date: 5/17/2023 11:59:00 PM (17%) Problem 6: A ball is suspended from a light 1.3 m string as shown. The string makes an angle of 25 degrees with the vertical. The ball is then kicked up and to the right such that the string remains taut the entire time the ball swings upwards. This kick gives the ball an initial velocity of 1.1 m/s. Huang, Liwei - Ihuang71@ucsc.edu L laterial. Theexpertta.com - tracking id: 6C65-12-37-43-A7B3-38903. In accordance with Expert TA's Terms of Service. copying this ormation to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. * 50% Part (a) What will be the speed, in meters per second, of the ball when it reaches its lowest point (0 = 0)? Grade Summary Deductions 11% Potential 39% sin() cos() tan() ( 7 8 9 HOME Submissions cotan( asin( acos( 4 5 6 Attempts remaining: 5 (1% per attempt) atan( acotan( inh( 1 2 3 detailed view cosh( tanh() cotanh() + END 1% O Degrees O Radians VO CLEAR 1% Submit Hint Feedback I give up! Hints: 3 for a 9% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. Gravitational Potential Energy is mgh. The height above the lowest point in this case is not simply _ times the sin or cos of the angle. What is initial height of the ball relative to the lowest point of it's trajectory? Use trigonometry to find it. -The direction of the initial velocity does not affect the final speed at the bottom. & 50% Part (b) What will be the maximum angle, in degrees, the string will make with the vertical