Class Management | Help Week2 Begin Date: 6/9/2023 12:01:00 AM -- Due Date: 6/20/2023 11:59:00 PM End Date: 8/10/2023 11:59:00 PM (4%) Problem 1: The car shown in the figure is moving towards the left, which is the negative r direction. It travels 28. 7 m during a 19.43-s time interval. 25% Part (a) What is the car's average speed, in meters per second, during the time interval? Vavg = 1.4770 Zavg = 1.477 m/s Correct! 25% Part (b) What is the sign of the r component of the car's velocity at any instant during the given time interval? The sign is negative. (-) Correct! $ 25% Part (c) What is the value of the T component of the car's average velocity, in meters per second, during the given time interval? m/s Grade Summary Deductions 0% Potential 100% sin() cos tan() TE ( ) 7 8 9 HOME Submissions cotan() asin() acos( ) E 4 5 6 Attempts remaining: 988 (0% per attempt) atan() acotan() sinh() 1 2 3 detailed view cosho tanh() cotanh() 0 10% 0% O Degrees O Radians VO 0% 0% Submit I give up! Hints: 1 for a 0% deduction. Hints remaining: Feedback: 0% deduction per feedback -Use the definition of average velocity in terms of the displacement and the elapsed time. Be careful with signs. 25% Part (d) In this case, must there be an instant at which the speed of the car is equal to its average speed? yes Correct! P10 OClass Management | H Week2 Begin Date: 6/9/2023 12:01:00 AM -- Due Date: 6/20/2023 11:59:00 PM End Date: 8/10/2023 11:59:00 PM (3%) Problem 10: A particle's velocity is directed along the +x-axis is described by v(t) = At + Bta, where the time t is in seconds and the velocity is in meters per second and A = 0.87 m/s and B = -0.55 m/s3 33% Part (a) What is the acceleration, in meters per second squared, of the particle at time to = 1.0 s? a(to) =- 0.23 a(to) - -0.2300 m/s- Correct! 33% Part (b) What is the displacement, in meters, of the particle between times to = 1.0 s and t, = 3.0 s? Ar - - 1 287 Ar - 1.287 m Correct! $3 33% Part (c) What is the distance traveled, in meters, by the particle between times to = 1.0 s and t = 3.0 s? d = m Grade Summary Deductions 0% Potential 100% sin() cos() tan() TE ( ) 7 8 9 HOME Submissions cotan() asin() acos( ) E 4 5 6 Attempts remaining: 996 (0% per attempt) atan() acotan() sinh() 1 2 3 detailed view cosh() tanh() cotanh() 0 0% 0% O Degrees O Radians VO 0% Submit Hint I give up ! Hints: 0% deduction per hint. Hints remaining: 3 Feedback: 0% deduction per feedback.Class Management | Help Week2 Begin Date: 6/9/2023 12:01:00 AM -- Due Date: 6/20/2023 11:59:00 PM End Date: 8/10/2023 11:59:00 PM (3%) Problem 11: The velocity of a ball in the horizontal direction is given as the following function: v(t) = 20 + 3+. where t is in seconds and the velocity is in meters per second. 33% Part (a) Find the change in the position, in meters, between t = 0 and t = 5.2 s. Ax = 652.37 Ax = 652.4 Correct!