Class Management | Help Week9 Begin Date: 7/27/2023 12:01:00 AM -- Due Date: 8/8/2023 11:59:00 PM End Date: 8/10/2023 11:59:00 PM (10%) Problem 23: The diagram shows four identical particles (labeled 1, 2, 3, and 4) that are moving in the x-y plane. The mass of each particle is 0.27 kg and they all move at the same speed of 18 m/s. Particle 1 is at (-4 m, 2 m) and is moving in the positive x direction. Particle 2 is at (4 m. 3 m) and traveling in the negative x direction. Particle 3 is at (0 m, -3 m) and moving in the positive y direction. Particle 4 is at (5 m, -3 m) and its velocity makes an angle of 45 degrees with the coordinate axes. 2 13 25% Part (a) What is the magnitude of the angular momentum of particle 1 about the origin? Express your answer in units of kg.m-/s. 1 =1 kg.m=/s Grade Summary Deductions 0% Potential 100% sin() cos() tan() It ( ) 7 8 9 Submissions cotan() asin() acos() 4 5 6 Attempts remaining: 999 (0% per attempt) atan() acotan( sinh( 1 2 3 detailed view cosh( tanh( cotanh() + 0 END Degrees O Radians VO Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback 4 25% Part (b) What is the magnitude of the angular momentum of particle 2 about the origin? Express your answer in units of kg.m-/s. A 25% Part (c) What is the magnitude of the angular momentum of particle 3 about the origin? Express your answer in units of kg.m-/s. 25% Part (d) What is the magnitude of the angular momentum of particle 4 about the origin? Express your answer in units of kg.m-/s.the Expert TA.com Student: telghazi2101@student.stcc.edu My Accour Class Management | Help Week9 Begin Date: 7/27/2023 12:01:00 AM -- Due Date: 8/8/2023 11:59:00 PM End Date: 8/10/2023 11:59:00 PM (5%) Problem 13: A thin cylindrical ring starts from rest at a height hy = 79 m. The ring has a radius R = 46 cm and a mass M = 10 kg. R 12 h, Otheexpertta.com 20% Part (a) Write an expression for the ring's initial energy at point 1, assuming that the gravitational potential energy at point 3 is zero. E1 = Mghi Correct! * 20% Part (b) If the ring rolls (without slipping) all the way to point 2, what is the ring's energy at point 2 in terms of h2 and 12? E2 = Mghy + 1/2 Mv2 X Attempts Remain * 20% Part (c) Given hy = 41 m, what is the velocity of the ring at point 2 in m/s? V2 = 27.2910 v2 = 27.29 X Attempts Remain * 20% Part (d) What is the ring's rotational velocity in rad/s at point 2? =59.3283 = 59.33 X Attempts Remain $20% Part (e) After passing point 2 the hill becomes frictionless and the ring's rotational velocity remains constant. What is the linear velocity of the ring at point 3 in m/s? Grade Summary Deductions Potential 10077.5 kg. (5%) Problem 11: Suppose you exert a force of 165 N tangential to the outer edge of a grindstone (which is a solid disk) with a radius of 1.4 m and a mass of 33% Part (a) What is the torque r, in newton meters, you are exerting on the grindstone, relative to the center of mass of the grindstone? T = 231.0 N . m / Correct! $ 33% Part (b) What is the angular acceleration of the grindstone co, in radians per square second, assuming negligible friction? 20 = 5.8 rad/s Grade Summary Deductions Potential 100 sin( coSO tan() 7 8 9 HOME Submissions cotan() asin( acos( E M 4 5 6 Attempts remaining: 99 atan() acotan() sinh() $ 1 2 3 (0% per attempt) detailed view cosho tanh() cotanh() + 0 END Degrees O Radians VO BACKSPACE DEL CLEAR Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. $ 33% Part (c) What is the angular acceleration of the grindstone at, in radians per square second, if there is an opposing frictional force of 18 N exerted 0.45 from the axis? Of = 5.61036 or = 5.610 rad/s X Attempts Remain(5%) Problem 9: Suppose we want to calculate the moment of inertia of a 68.5 kg skater, relative to a vertical axis through their center of mass. 50% Part (a) First calculate the moment of inertia (in kg.m-) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.145 m. It = 0.7200 - Correct! * 50% Part (b) Now calculate the moment of inertia of the skater (in kg.m-) with their arms extended by assuming that each arm is 5% of the mass of their body. Assume the body is a cylinder of the same size, and the arms are 0.85 m long rods extending straight out from the center of their body being rotated at the ends. 1 = 0.18 Grade Summary Deductions 0% Potential 100% sin cos() tan() TE ( ) 7 8 9 HOME Submissions cotan( asin() acoso EM 4 5 6 Attempts remaining: 995 (0% per attempt) atan() acotan() sinh( 1 $ 1 2 3 detailed view cosh( tanh( cotanh() + 0 END 0% 0% Degrees O Radians VO BACKSPACE DEL CLEAR 0% 09% Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback.(5%) Problem 8: Consider two cylindrical objects of the same mass and radius. Object A is a solid cylinder, whereas object B is a hollow cylinder.