Click and drag the steps in the correct order to show that if n is a positive integer, then n is even if and only if 7n+ 4 is even Suppose that n is even Then, 7n414k4-2(7k 2) Since n is even, it can be written as 2k for some integer k. This is 2 times an integer; so it is even as desired Then, 7n + 4 = 14k + 2 = 2(7k+ 1). Suppose that n is not even. Then, n can be written as 2k+1 for some integer k. Thus, 7n+4-14k+11-2(7k +5)+1 Thus, 7n4 14k +10 2(7k +5) This is 1 more than 2 times an integer, so it is odd