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Coding Help! This is question 3, but see a link below for Q1 and Q2 answered for a reference. Coding language Python, Thanks!!! Now, write

Coding Help! This is question 3, but see a link below for Q1 and Q2 answered for a reference. Coding language Python, Thanks!!!

Now, write code to create a bar plot of the number of entries in the sub-intervals. The x coordinates of the bars are the mid points of the intervals and the heights are the total number of elements of the array x residing in each interval (basically the results from your function above). Look up the function matplotlib.pyplot.bar. Set the widths of the bars to the width of each subinterval.

Repeat the experiments in Questions 1 and 2 and generate the bar plots for =20S=20 and =102n=102, =103n=103, and =105n=105 (three cases). Make sure to label all the x and y axes and give each plot an expressive title that indicates the value of n. Matplotlib contains the function subplot() that enables making multiple plots and arranging them together. Plot the three bar plots for the three values of n together in a single row. Use the command plt.tight_layout() to arrange the subplots cleanly.

(Below are Questions 1 & 2 for reference)

https://www.chegg.com/homework-help/questions-and-answers/question-2-3-need-help-shows-work-question-1-well-generate-array-x-100n-100-random-numbers-q44213803

Generate an array x that has =100n=100 random numbers that are uniformly distributed over the interval [0,1)[0,1). Look up how to use the uniform() submodule of numpy.random for this question.

In [7]:

x = np.random.uniform(0,1,100)
x

Out[7]:

array([0.7686359 , 0.00193933, 0.46081786, 0.46102876, 0.68163423, 0.14500163, 0.45691225, 0.7292489 , 0.90528235, 0.0911936 , 0.67765543, 0.38597125, 0.71937148, 0.15770145, 0.49757855, 0.54101159, 0.66140345, 0.27425061, 0.5645736 , 0.76021416, 0.10858791, 0.23388888, 0.2446358 , 0.77459127, 0.28161746, 0.13943564, 0.04875112, 0.31839392, 0.3419016 , 0.13703515, 0.96244035, 0.7650515 , 0.45154491, 0.16891573, 0.84509981, 0.83959792, 0.01358548, 0.70807755, 0.80747734, 0.82473523, 0.15618429, 0.78666749, 0.57486057, 0.5219147 , 0.33921758, 0.35436014, 0.06144321, 0.40319046, 0.20456046, 0.32178498, 0.11046061, 0.19810378, 0.66004367, 0.20883655, 0.58052234, 0.68550039, 0.3471392 , 0.46675729, 0.73755096, 0.32242399, 0.78330108, 0.69362819, 0.73173772, 0.97009438, 0.49582071, 0.72609253, 0.99586097, 0.79207091, 0.70651406, 0.48064219, 0.31361071, 0.20625934, 0.50786544, 0.23537456, 0.79965622, 0.22791709, 0.40573057, 0.1608864 , 0.33956229, 0.21248393, 0.98982715, 0.03081672, 0.21761966, 0.59420732, 0.32359678, 0.48700202, 0.2058104 , 0.81784287, 0.00118625, 0.71005526, 0.82820403, 0.47965642, 0.96900737, 0.87204295, 0.70630899, 0.59851428, 0.15654434, 0.31299372, 0.40188938, 0.97215467])

Question 2: We want to divide the numbers in the interval [0,1)[0,1) into equally spaced sub-intervals. For example, say we want to take an array of 100 numbers that have values greater than or equal to 0 and less than 1. We might like to divide these numbers into 4 equally spaced half-open sub-intervals: 0 to 0.25; 0.25 to 0.5; 0.5 to 0.75; and 0.75 to 1.

Write a function named partition_array using loops and if statements that takes the array x along with the number S of sub-intervals as inputs and outputs (returns) a new list numentries_subintervals with S entries. Each entry in numentries_subintervals will contain the number of values from x within each of the sub-intervals. The function will also output a second list that contains the mid points of each corresponding sub-interval. Test it on the array generated in Question 1, use =5S=5 subintervals, and print the function outputs to verify the results.

NOTE: You can assume that your input array x will have values in the interval [0,1)[0,1).

def partition_array(x,S): h=1/S numentries_subintervals=[0]*S intervals=[] midPoints=[] for i in range(S): intervals.append((i+1)*h) midPoints.append(((i+1)*h+i*h)/2)#midpoint for i in x: for j in range(len(intervals)): if i

x = np.random.uniform(0,1,100) numentries_subintervals,midPoints=partition_array(x,5) print('The number of entries in the subintervals are',numentries_subintervals) print('The subinterval mid points of the intervals are',midPoints)

The number of entries in the subintervals are [15, 18, 19, 26, 22] The subinterval mid points of the intervals are [0.1, 0.3, 0.5, 0.7, 0.9]

In [ ]: # Put your pseudocode, in the form of comments, and code here

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