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Compiler Design - Regular Expressions 5. Show that RS !- SR by giving a counterexample (R and S are regular expressions.) 6. Show that (R
Compiler Design - Regular Expressions
5. Show that RS !- SR by giving a counterexample (R and S are regular expressions.) 6. Show that (R | S)* '= (R* | s*) by giving a counterexample. (R and S are regular expressions.) Also: Is (R | S)* = (R* 1 s*)" ? Yes, no and whyStep by Step Solution
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