Compute (1f)h , with h and f as specified above. Change the my_array_ref so that instead of returning zero when the index is out of bounds, it should return the boundary value, i.e., for f(-2, 3) and f (2, 15), it should return f(0, 3) and f(2, 9), respectively. Re-compute (1f)h , with h and f as specified above, but using this new my_array_ref function. Compare the output obtained in step 3 above with that in step 1.