Question: Compute 2 1 0 1 1 1 3 0 by applying the divide - and - conquer algorithm A . c 2 = 2 1

Compute 21011130 by applying the divide-and-conquer algorithm
A.
c2=21*11
c0=01*30
c1=(21+01)*(11+30)-(c2+ c0).
then 21011130= c2103+ c1102+ c0101
B.
c2=21*11
c0=01*30
c1=(21+01)*(11+30)-(c2+ c0).
then 21011130= c0104+ c1104+ c2104
C.
c2=21*11
c0=01*30
c1=(21+01)*(11+30)-(c2+ c0).
then 21011130= c2104+ c1102+ c0
D.
c2=21*11
c0=01*30
c1=(21+01)*(11+30)-(c2+ c0).
then 21011130= c2104+ c1104+ c0104

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