Compute the critical value Za/2 that corresponds to a 97% level of confidence. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Za /2 = (Round to two decimal places as needed.)on 9.1 Determine the point estimate of the population proportion, the margin of error for the following confidence interval, and the number of individuals in the sample with the specified characteristic, x, for the sample size provided. Lower bound = 0.227, upper bound = 0.713, n = 1200 . . . The point estimate of the population proportion is (Round to the nearest thousandth as needed.)Construct a 90% confidence interval of the population proportion using the given information. X = 60, n = 300 E Click here to view the table of critical values. The lower bound is The upper bound is (Round to three decimal places as needed.)In a survey of 2085 adults in a certain country conducted during a period of economic uncertainty, 62% thought that wages paid to workers in industry were too low. The margin of error was 3 percentage points with 95% confidence. For parts (a) through (d) below, which represent a reasonable interpretation of the survey results? For those that are not reasonable, explain the flaw. . . . (a) We are 95% confident 62% of adults in the country during the period of economic uncertainty felt wages paid to workers in industry were too low. Is the interpretation reasonable? O A. The interpretation is reasonable. O B. The interpretation is flawed. The interpretation provides no interval about the population proportion. O C. The interpretation is flawed. The interpretation suggests that this interval sets the standard for all the other intervals, which is not true. O D. The interpretation is flawed. The interpretation indicates that the level of confidence is varying.A researcher wishes to estimate the proportion of adults who have high-speed Internet access. What size sample should be obtained if she wishes the estimate to be within 0.03 with 95% confidence if (a) she uses a previous estimate of 0.48? (b) she does not use any prior estimates? Click the icon to view the table of critical values. . . . (a) n= (Round up to the nearest integer.)In a poll, 69% of the people polled answered yes to the question "Are you in favor of the death penalty for a person convicted of murder?" The margin of error in the poll was 3%, and the estimate was made with 94% confidence. At least how many people were surveyed? Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). . . . The minimum number of surveyed people was (Round up to the nearest integer.)A group conducted a poll of 2044 likely voters just prior to an election. The results of the survey indicated that candidate A would receive 47% of the popular vote and candidate B would receive 45% of the popular vote. The margin of error was reported to be 2%. The group reported that the race was too close to call. Use the concept of a confidence interval to explain what this means. What does it mean to say the race was too close to call? O A. Since the estimated proportions depend on the level of confidence, the candidate predicted to receive the greater percentage of the popular vote changes for different levels of confidence, so the poll cannot predict the winner. O B. Since the difference between the percentages of the popular vote for the candidates is less than the 8% of voters that are undecided, the poll cannot predict the winner. O C. The margin of error suggests candidate A may receive between 45% and 49% of the popular vote and candidate B may receive between 43% and 47% of the popular vote. Because the poll estimates overlap when accounting for margin of error, the poll cannot predict the winner. O D. Since the poll results do not show that one of the candidates has more than 50% of the popular vote, the poll cannot predict the winner.By how many times does the sample size have to be increased to decrease the margin of error by a factor of ~? The sample size must be increased by a factor of to decrease the margin of error by a factor of (Type a whole number.)Katrina wants to estimate the proportion of adults who read at least 10 books last year. To do so, she obtains a simple random sample of 100 adults and constructs a 95% confidence interval. Matthew also wants to estimate the proportion of adults who read at least 10 books last year. He obtains a simple random sample of 400 adults and constructs a 99% confidence interval. Assuming both Katrina and Matthew obtained the same point estimate, whose estimate will have the smaller margin of error? Justify your answer. . . . Whose estimate will have the smaller margin of error and why? O A. Katrina's estimate will have the smaller margin of error because the lower level of confidence more than compensates for the smaller sample size. O B. Matthew's estimate will have the smaller margin of error because the larger sample size more than compensates for the higher level of confidence. O C. Matthew's estimate will have the smaller margin of error because the sample size is larger and the level of confidence is higher. O D. Katrina's estimate will have the smaller margin of error because the sample size is smaller and the level of confidence is lower