Compute the outward flux of the vector field j|'(ma y, z) = {mi + lyj + 3:]: across the boundary of the right cylinder with radius 4 with bottom edge at height 2 : -2 and upper edge at z = 4. Note: The vectors in this field point outwards from the origin, so we would expect the flux across each face of the cylinder to be positive. Part 1 - Using a Surface Integral First we parameterize the three faces of the cylinder. Note: in the following type 6 as theta. The bottom face: (710, 9) = (931039): y1(1",9)g 210-, .9) where 0 S 9 5 2m 0 S r S 4 and $10\