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Compute the volume of the solid the lies below the surface z = f (x, y) = x+2y^2 and above the rectangle R = [0,2][0,4]
Compute the volume of the solid the lies below the surface z = f (x, y) = x+2y^2 and above the rectangle R = [0,2][0,4] as the limit of a Riemann sum. Be careful if you attempt this problem because you can actually be awarded negative extra credit points if you do not obtain the answer by taking the limit of Riemann sums.
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