computer networks

.... Question 4 (6 Marks) Given below a Point-to-point communication trace taken by Wireshark a network protocol analyzer software. ETHER: ----- Ethernet Header ----- ETHER: Packet 3 arrived at 11:42:27.64 ETHER: Packet size = 64 bytes ETHER: Destination - 9:0:20:18:ba:40 ETHER: Source = aa:0:4:0:1f:ce ETHER: Ethertype = 0800 (IP) IP: ----- IP Header ---- IP: Version = 4 IP: Header length = 20 bytes IP: Type of service - Ox00 IP: xxx. .... = 0 (precedence) IP: ...0.... = normal delay IP: ....0... - normal throughput IP: .0.. = normal reliability IP: Total length = 40 bytes IP: Identification = 41980 IP: Flags = 0x4 IP: .1.. = do not fragment IP: ..0. - last fragment IP: Fragment offset = 0 bytes IP: Time to live = 63 seconds/hops IP: Protocol = 6 IP: Header checksum = af 63 IP: Source address = 163.173.32.65 IP: Destination address = 216.58.207.4 IP: No options TCP: ----- TCP Header ----- TCP: Source port - 1368 TCP: Destination port = 25 (SMTP) TCP: Sequence number - 143515262 ICP: Acknowledgement number = 3128387273 TCP: Data offset - 20 bytes TCP: Flags = Ox10 TCP: ..0. - No urgent pointer TCP: ...1 = Acknowledgement TCP: 0... - No push TCP: .....0.. = No reset TCP: ...0. = No Syn TCP: .0 - No Fin TCP: Window = 32120 TCP: Checksum = Ox3c30 TCP: Urgent pointer - O TCP: No options .... Analyse the above trace and indicate the following: a) The protocol used in each of the following layers: Data Link, Network, Transport and Application [2] b) Source and destination MAC addresses [1] c) Source and destination IP addresses. [1] d) Explain the value 0x10 shown in the flags field (highlighted in blue color in the trace) by indication the type of this captured message? [1] e) Explain the meaning of the value shown in window size (highlighted in blue color in the trace)? [1] Page 15