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concatenate Implement a method which takes two LinkedIntLists as input and returns a new list containing all the items of the first followed by all

concatenate
Implement a method which takes two LinkedIntLists as input and returns a new list containing all the items of the first followed by all the items of the second. Dont modify the input lists; use the new keyword to create new objects instead. Your implementation should run in linear time i.e. without the use of nested for-loops.
list1: front ->1->2->3->/
list2: front ->4->5->6->/
If you made the call concatenate(list1, list2), then it should return a new list:
return: front ->1->2->3->4->5->6->/
and list1 and list2 would remain unchanged:
list1: front ->1->2->3->/
list2: front ->4->5->6->/

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