Conclusion: a. Summarize your results and analysis and refer back to your hypotheses b. What does the resistance of the wire tell you about the conductivity of the wire (its ability to conduct electricity)? c. If you were to set up a circuit, describe the characteristics of the wire you would use to have the best conductivity (ie. material, thickness and length) Analysis: Part A: Different Diameters wires wire 3 wire 4 calculations R=V/I R=V/1 R=0.5V/0.1A R=0.5V/0.02A R=50 R= 250 Different lengths (part B) Wire wire 3 wire 3 wire 3 Lengths 25m 50m 75m current intensity 0.2A 0.14 A 0.12A calculations R=V/1 R=V/1 R=V/1 R=0.5V/0.2A R=0.5V/0.14A R=0.5V/0.12A R= 2.50 R= 3.570 R= 4.160Hypothesis: If the wire is thinner then more electricity will come through.Factors affecting the Resistance/conductivity of a Wire The purpose of this lab is to demonstrate how 3 variables affect the ability of a conductor to carry electric current by measuring the current intensity: i. Diameter or thickness of a wire ii. Length of a wire iii. Material Materials: 0 4 wires on a conductivity board 0 Wires #1: iron, 22 gauge 0 Ammeter #2: copper, 22 gauge 0 Power source #3: nichrome, 22 gauge #4: nichrome, 26 gauge Procedure: The initial set-up will be explained in class (set power supply to 0.5 V) Part A: Different Diameters 1. Attach the wires to the very ends of wire #3(22 gauge thicker), record current intensity 2. Repeat for wire #4 (26 gauge thinner), record current intensity Part B: Different lengths 1. Attach one wire to the end of wire #3, touch the other wire to the 25 cm mark, record current intensity 2. Repeat for the 50 cm mark and the 75 cm mark, record current intensity Part C: Different materials 1. Attach the wires to the very ends of wire #1 (iron), record current intensity 2. Repeat for #2(copper) and #3 (nichrome), record current intensity Different materials (part C) wire wire 1 (iron) wire 2 (copper ) wire 3 (nichrome ) power supply 0.5v 0.5v 0.5v current intensity 10.2A 0.22A 0.1A calculations R=V/I R=V/1 R=V/1 R=0.5V/0.2A R=0,5V/0,22A R=0.5V/0.1A R=2.50 R=2.270 R=50