Question
Consider a chocolate manufacturing company that produces only two types of chocolate - A and B. Both the chocolates require Milk and Choco only. To
Consider a chocolate manufacturing company that produces only two types of chocolate - A and B. Both the chocolates require Milk and Choco only. To manufacture each unit of A and B, the following quantities are required:
Each unit of A requires 1 unit of Milk and 3 units of Choco
Each unit of B requires 1 unit of Milk and 2 units of Choco
The company kitchen has a total of 5 units of Milk and 12 units of Choco. On each sale, the company makes a profit of P 6 per unit A sold P 5 per unit B sold.
Now, the company wishes to maximize its profit. How many units of A and B should it produce respectively?
Solution:
Milk | Choco | Profit per unit | |
A | 1 | 3 | 6 |
B | 1 | 2 | 5 |
TOTAL | 5 | 12 |
Let X is total number of units produced by A
Let Y is total number of units produced by A and Z is the total profit
how to calculate the total profit of the company
just multiply the total number of units A and B produced and Per unit profit
6 and 5 respectively
so Profit Max Z=6X+5Y
That means we need to maximize the profit z
The company will try to maximize the profit by producing as many as units of A and B
but the problem is Milk and Choco resources are limited from the table,
A and B need 1 unit of Milk
But the Milk is available only 5 units
how to represent this in mathematically
X+Y<=5
And
each unit of A, B need 3 ,2 units of Choco
but total amount of Choco is only 12 units again,
represent it mathematically
3X+2Y<=12
A can only integer value
and we have 2 more constraints
X>=0
Y>=0
Therefore, X=2, Y=3
Z= 6X+5Y
Z= 6*2+5*3
Z=27
Question:
How to prepare the Graphical Solution of the Problem?
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