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Consider a distribution with the probability density function f(y;u)=[1/(2xy3)]-(1/2) expl-(y-1)2/(2uzy)] where u is the mean of the distribution and y>0. What is the variance function,
Consider a distribution with the probability density function f(y;u)=[1/(2xy3)]-(1/2) expl-(y-1)2/(2uzy)] where u is the mean of the distribution and y>0. What is the variance function, V(), of this distribution? Notes: (i) Precisely one answer below is correct and the others are incorrect. (ii) An incorrect answer scores zero while the correct answer scores full marks for the question. Select one: O a. V(u)=2u2 O b. V(u)=3 O c. V(u)=243 O d. V(u)=12
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