Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.550 cm and an area of 0.710 m, separated by a layer of air with a thickness of 1.95 cm. The temperature on one side of the window is 0.00 C; the temperature on the other side is 25.0 C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Strategy: Because the thermal conductivity of air is much smaller than the thermal conductivity of glass, most of the temperature difference between the inside and outside will occur across the air. Assuming the full temperature difference is across the air, calculate the heat flow through the window using the equation Q= kAt. Solution: Apply the equation: - kAAT= (0.0234 W/(m-K)] (0.710 m)(- Part B AT= Use the approximate heat flow found in part A to find an approximate temperature difference across each pane of glass. (The exact result is 0.193 C.) View Available Hint(s) IVE S ? 25.0 C 1.95102 m. C -)= 21.3 J/s