Consider a human femur of length L = 448 mm. Model the bone as a hollow cylinder, with inner radius Ra = 4.87 mm and outer radius Rb = 14.61 mm. If a 70 kg person's weight is supported by one leg, calculate the stress on the femur; express your answer as a percentage of the UCS, where the UCS of a bone under compression is 162 MPa. Ignore the weight of the leg and round your answer to the second decimal place. HINT: To express as a percentage of the UCS multiply the stress by 100/UCS. Do not enter any units as they will cancel out. Your Answer: 0.71 Please answer this ! Assuming that the bone in the previous question (L = 448 mm; UCS = 162 MPA; Y = 10600 MPA) obeys Hooke's Law right up to the breaking point, what is the total compression of the bone right before breaking? Answer in units of mm. Round to the first decimal place."