Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Consider a random variable X with quantile function Q X (p). (a) Let Y = g(X), with g a strictly increasing and continuous function. Show

Consider a random variable X with quantile function QX(p).

(a) Let Y = g(X), with g a strictly increasing and continuous function. Show that QY(p) = g(QX(p)). (i.e., the quantile function of a strictly increasing transformation is the transformation of the quantile function.)

(b) Now let Y = g(X), with g a strictly decreasing and continuous function. Further suppose that the CDF FX of X is strictly increasing on its support X. How does QY(p) relate to QX(p) in this case?

(c) Suppose that QX(p) is differentiable at every point p (0, 1). Using the formula for the derivative of an inverse function, show that Q'X(p) = 1/(fX(QX(p))) . [Note: QX can be differentiable only if FX is strictly monotone and differentiable on the support X of X.]

Note: A quantile can be thought of as the inverse CDF.

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image_2

Step: 3

blur-text-image_3

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Oscillations In Nonlinear Systems

Authors: Jack K Hale

1st Edition

0486803260, 9780486803265

More Books

Students also viewed these Mathematics questions

Question

=+f. Audience Engagement encourage consumer participation.

Answered: 1 week ago

Question

=+d. Emotional Approach appeal to consumers' emotions.

Answered: 1 week ago