Consider a relational schema for storing information related to movies: Actor(name, YofB, country_of_birth, bio) Director(name, YofB, country_of_birth, bio) Producer(name, YofB, country_of_birth) Country(code, name) Movie(title, year, genre, budget, gross_earnings) DirectorMovie(d name, d YofB, m_title, m_year) ActorMovie(a name, a YofB, m title, m year) ProducerMovie(p name, p YofB, m title, m year) Actor[country_of_birth] Country[code] Director[country_of_birth] Country[code] Producer[country_of_birth] Country[code] DirectorMovie [d_name, d_YofB] Director[name, YofB] DirectorMovie[m_title, m_year] Movie [name, year] ActorMovie [a_name, a_YofB] Actor[name, YofB] ActorMovie [m_title, m_year] Movie[name, year] ProducerMovie [p_name, p_YofB] Producer[name, YofB] ProducerMovie [m_title, m_year] Movie [name, year] Attribute genre in table Movie has as value one of {"comedy", "drama", "tragedy", "musical", "horror"}. Attributes YofB and year have integer values, e.g., 2022. Atributes budget and gross_earnings have integer values, e.g., 1 000 000. Attributes code and name in relation Country have values such as, "CAN", "GBR", and "Canada", "United Kingdom", respectively. Write the following queries in Relational Algebra. a. Find the producers who also acted in a movie they produced. Return their names and year of birth. b. Find producers who were younger than all the actors of the movies they produced. Return their name and year of birth. c. Find producers who only produced comedies and dramas. Return their name and year of birth. d. Find actors who never acted in a tragedy. Return their name and year of birth.