Consider a set with $20$ elements.

How many possible ways are there to create a subset with $11$ elements? $($Hint: The third digit of the

solution is greater than $6)$

Consider the expression $\frac{20!}{m!}.$ What value of $m$ would make the expression equivalent to the number

of ways you could pick, in order and without replacement, $4$ elements from the set? $($Hint: Notice the

factorial symbol in the denominator$)$