Question
Consider a simple system with 8-bit block size. Assume the encryption (and decryption) to be as follows: If plaintext is LT||RT and the key is
Consider a simple system with 8-bit block size. Assume the encryption (and decryption) to be as follows: If plaintext is LT||RT and the key is LK||RK, where LC, RC, LT, and RT are each 4 bits, then ciphertext= LC||RC where LC=LK XOR RT; and RC = RK XOR LT; Plaintext and ciphertext are each 8 bits. Similarly, to decrypt ciphertext, we perform exactly the reverse operation where LT=RC XOR RK and RT = LC XOR LK. You are given the following 16-bit input B5D7 (in Hexa). You are provided IV as: E8 (hexa).
For CTR assume the stream of bits to be used for counter to be starting from 0001 and incremented by 1 every time; so the stream would be 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110 1111 0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110 1111
The 8-bit key to be used (where appropriate) is 3C (hexa).
Compute the encrypted output with (i) ECB (ii) CBC (iii) OFB (iv) CFB (v) CTR (with IV=0011) Express the output as 4 hexa characters so it is easy to read.
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started