Consider a two-component standby with non-identical components arranged in a parallel configuration. Let 1 and 2 be the components. Initially, 1 is the working component and 2 is in the standby mode. The hazard rates are given as follows: 1= 0.02/month, 2= 0.05/month and 2 = 0.01/month. Compute the design life corresponding to a desired reliability of 0.6 [Hint: You can use trial and error approach to calculate design life)