Consider accomplishing the reaction $A+$BlongrightarrowC in a non$-$isothermal batch reactor. The

reaction occurs in the liquid phase. Find the time necessary to reach $75\%$ conversion.

a$)$ If the coolant supply is sufficient to maintain the reactor wall at $315K.$

b$)$ If the reactor is now adiabatic, plot the conversion and temperature as a function of time.

How much energy is removed from the reactor when it is operated non$-$isothermally?

$($MATLAB$/$PHYTON$)$

Additional Data

$C_{A0}=0\mathrm{.}4mo\frac{l}{L},N_{A0}=80$mol

$C_{B0}=0\mathrm{.}6mo\frac{l}{L},k=0\mathrm{.}003$exp$[(25000\frac{\frac{J}{m}ol}{R})**(\frac{1}{315}-\frac{1}{T})](\frac{L}{m}o\frac{l}{s})$

$C_{PA}=C_{PB}=55\frac{J}{m}ol*K,U{A}_H=40\frac{J}{s}*K$

$C_{PC}=150\frac{J}{m}ol*K,H_{rx}=-20k\frac{J}{m}ol$