Consider an object that is given an initial potential energy Us by a compressed spring. The object is then "launched", converting all of the spring potential energy into kinetic energy. Conservation of energy tells us that the total mechanical (potential + kinetic) energy of a system is conserved for a frictionless process. Thus the total energy E0 at the start of the process is equal to the total energy Ef at the end of the process. In this situation, E0 = Us and Ef is equal to the kinetic energy K of the object. You can then write: 1/2kl2 = 1/2mv2 where k = 7 N/m is the spring constant and m = 0.6 kg is the mass of the object. Suppose the spring is compressed distance l1 = 0.070 m and this gives the object a speed v1. Next suppose the spring is compressed distance l2 = 0.14 m and this gives the object a speed v2. What is the ratio v2/v1? Give numerical answer to two significant figures