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Consider lim x In(4x). 2 + 00 What is the indeterminate form? 10 . 00 0 10 0 0 O 00 Part 2 of 3

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Consider lim x In(4x). 2 + 00 What is the indeterminate form? 10 . 00 0 10 0 0 O 00 Part 2 of 3 How should we rewrite the limit? 2 - 2 O. In(4x) In(4x) O - 2 - 2 In ( 4x ) In(4x) O 2 2 Part 3 of 3 Now, apply L'Hospital's Rule to evaluate the limit lim x 2 In(4x) = Question Help: Message instructor Post to forumPart 1 of 3 Consider lim What is the indeterminate form? 0 0 . 00 0 O 0 0 10 Part 2 of 3 How should we rewrite the limit? - x 2 - 2 Part 3 of 3 Now, apply L'Hospital's Rule to evaluate the limit limPart 1 of 4 Use L'Hospital to determine the following limit. Use exact values. lim (1 + sin 10x) 7 = x -0 What form is this limit? 0 0 O 0 0 . 00 Part 2 of 4 How should we rewrite the limit? Oeln (1 + sin (10x ) ) Oer . In (1 + sin ( 10x) ) 1 + sin ( 10x ) 1 + sin (10x) ac Part 3 of 4 Now we focus on the limit of just the exponent, - In(1 + sin 10x). lim - In(1 + sin(10x)) = x -0 x Question Help: Message instructor D Post to forumUse L'Hospital to determine the following limit. Use exact values. lim (1 1) 3:407 :13 What form is this limit? 02 0 Ol @000 00-00 00'\" 02 00 ow J Part 2 of 4 How should we rewrite the limit? Om@%) ml Oeln(1_%) Part 3 of 4 1 Now we focus on the limit of just the exponent, :1: 111(1 ) . 13 1m \"(1 l) = [: :n>O' 93 \f26. lim sin x In x37. lim x1/(1-x) x-1+

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