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Consider the circuit ( Assume R 1 = 1 2 . 0 Omega , R 2 = 2 . 2 0 Omega
Consider the circuit Assume ROmega ROmega and V V
A rectangular circuit begins at the positive terminal of a battery labeled V which is on the bottom side of the rectangle. The circuit extends up and to the left to resistor labeled R on the top side of the rectangle. To the right of R the circuit splits into two parallel horizontal branches.
The top branch splits into two parallel horizontal subbranches. There is a resistor labeled R on the top subbranch and a resistor on the bottom subbranch. The subbranches then recombine and the top branch extends to the right to a resistor.
The bottom branch contains a resistor.
The top and bottom branches then recombine and the circuit extends down and to the left until it reaches the negative terminal of the battery.
a Calculate the equivalent resistance of the R and Omega resistors connected in parallel.
Omega
b Using the result of part a calculate the combined resistance of the ROmega and Omega resistors.
Omega
c Calculate the equivalent resistance of the combined resistance found in part b and the parallel Omega resistor.
Omega
d Combine the equivalent resistance found in part c with the R resistor.
Omega
e Calculate the total current in the circuit.
A
f What is the voltage drop across the R resistor?
V
g Subtracting the result of part f from the battery voltage, find the voltage across the Omega resistor.
V
h Calculate the current in the Omega resistor.
A
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