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Consider the code fragment below: # a0 has address of C array # a1 has address of D array # a2 has size of C
Consider the code fragment below: # a0 has address of C array # a1 has address of D array # a2 has size of C array (2500) # a3 has size of D array (2500) a2, $a2, 2 a3, $a3, 2 vO, zero, zero $t0, $zero, zero add add outer: add $t4, 0 ($t4) $t1, $zero, $zero add inner: add $t3, 0 ($t3) $t3, $t4, skip vO, $v0, 1 bne addi addi bne addi bne skip: $tl, a3, inner $t0, $t0, 4 $t0, a2, outer Comment thecode State in a single short sentence what the PROGRAM actually does The guality of your comments will help with partial credit Ior an incorrect
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