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Consider the definition h(n) = { 1 if n=1, h(n-1) +h([n/2]) + 1 if n > 1 An obvious algorithm to compute h is a

Consider the definition

h(n) = { 1 if n=1, h(n-1) +h([n/2]) + 1 if n > 1

An obvious algorithm to compute h is a recursive one, directly based on the above definition . Is that algorithm efficient ? Why or why not , if not how can the algorithm be improved ? justify your answer

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