Consider the differential equation y''-3y'-18y=6e^(-3x)

Find a particular solution to the differential equation having form yp=u1y1+u2y2

Consider the differential equation y" 3y' 18y = 6e'3" (where primes indicate derivatives with respect to x). Find a particular solution to the differential equation having the form J'p = \"1% + uzyz using the method of Variation of Parameters. In this, (Note that this asks for \"'1 and u , not Lu and uQ !) y1 = 3'2 = u'l = u'2 = Then use your solution to find a solution to the differential equation that satisfies the initial conditions y(0) = 0, y" (0) = 0. y =