Consider the equation 4 + ;=2 . The graph of this curve looks like this: (xl)2 + y2 (x+1)2 +1.!2 yuis xmis (a) Find the
Consider the equation 4 + ;=2 . The graph of this curve looks like this: (xl)2 + y2 (x+1)2 +1.!2 yuis xmis (a) Find the positive yintercept: (b) Find the negative yintercept: (c) Use implicit differentiation to find the equation of the tangent line at the intercept in (a): (C!) Use implicit differentiation to find the equation of the tangent line at the intercept in (b)
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