Consider the equilibrium between (CH3)2CHOH, (CH3)2CO and H. (CH3)2CHOH(g) (CH3)2CO(g) + H(g) K = 2.00E-2 at 467 K The reaction is allowed to reach equilibrium in a 12.0-L flask. At equilibrium, [(CH3)2CHOH] = 0.298 M, [(CH3)2CO] = 7.72E-2 M and [H] = 7.72E-2 M. (a) The equilibrium mixture is transferred to a 6.00-L flask. In which direction will the reaction proceed to reach equilibrium? to the right OR to the left (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 6.00-L flask. [(CH3)2CHOH] = M [(CH3)2CO] = M [H] M