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Consider the following aqueous equilibrium. CH 3 COOH(aq) + H 2 O(l) CH 3 COO - (aq) + H 3 O + (aq) K c
Consider the following aqueous equilibrium.
CH3COOH(aq) + H2O(l) CH3COO-(aq) + H3O+(aq) Kc = 4.3 x 10-4
What is the role of H2O in this equilibrium?
A. | H2O is acting as the conjugate base to CH3COOH | |
B. | H2O is acting as the acid | |
C. | H2O is acting as the conjugate acid to CH3COO- | |
D. | H2O is acting as the conjugate acid to CH3COOH | |
E. | H2O is acting as the base |
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