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Consider the following aqueous equilibrium. CH 3 COOH(aq) + H 2 O(l) CH 3 COO - (aq) + H 3 O + (aq) K c

Consider the following aqueous equilibrium.

CH3COOH(aq) + H2O(l) CH3COO-(aq) + H3O+(aq) Kc = 4.3 x 10-4

What is the role of H2O in this equilibrium?

A.

H2O is acting as the conjugate base to CH3COOH

B.

H2O is acting as the acid

C.

H2O is acting as the conjugate acid to CH3COO-

D.

H2O is acting as the conjugate acid to CH3COOH

E.

H2O is acting as the base

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