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Consider the following cell at 2 5 deg C: Pt | Ti 2 + , Ti 3 + ( a = 0 . 2

Consider the following cell at 25\deg C:
Pt|Ti2+,Ti3+(a =0.25)||Cl-(a=0.4)|CuCl|Cu
The cell has a current of 0.02A passing through it, and experiences a resistance of 5\Omega .
The data for the half cells is given as follows:
Half cell half cell reaction E\deg (V)
Pt|Ti2+,Ti3+ Ti3++ e--> Ti2+-0.369
Cu|CuCl|Cl- CuCl + e--> Cu + Cl-+0.137
Calculate the EMF, E, of the cell

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