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Consider the following code segment. CLR MOV.W MOV.W 01 02 03 04 05 1nxt: 06 07 MOV.B BIT.W JNZ INC 08 1skip: RRA.W 09
Consider the following code segment. CLR MOV.W MOV.W 01 02 03 04 05 1nxt: 06 07 MOV.B BIT.W JNZ INC 08 1skip: RRA.W 09 DEC.B JNZ MOV. B PPO OHNM 10 11 R12 mylw, R6 #1, R5 #16, R7 R5, R6 lskip R12 R6 R7 Inxt R12, P2OUT 12 13 mylw: .long 0x8C9E2A7D " 30 30 30 30 30 (15 points) What does this code segment do? Explain your answer. 3.D. (5 points) Calculate the total execution time in seconds for the code sequence from above (line 01 - line 11). We know the following: the average CPI is 2 clocks per instruction. Assume the clock frequency is 1 MHz. What is MIPS rate for this code?
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To calculate the total execution time in seconds for the code sequence from line 01 to line 11 we need to know the number of clock cycles required for each instruction and the clock frequency Given th...
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Elementary Statistics A Step By Step Approach
Authors: Allan G. Bluman
9th Edition
0077665805, 9780077665807
