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Consider the following definitions: unsigned char f ( unsigned char b ) return b + 2 ; unsigned char c = 0 x F F

Consider the following definitions:
unsigned char f(unsigned char b) return b+2;
unsigned char c=0xFF;
int n=1,A[4]={8,4,2,1};
float y=0.4f;
const char **S="Hi!";
Assuming widths of char, short, int and long are 8,16,32 and 64 bits respectively, pointer size is
8 bytes, evaluate each expression. In addition to their value, determine the type of their result.
a)c+2+f(c)
b)s[4]&&++n? y : n;
c)n=sizeof(A)+sizeof(S)
d)c
e)y**1.+c10
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